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7x=-5x^2+10
We move all terms to the left:
7x-(-5x^2+10)=0
We get rid of parentheses
5x^2+7x-10=0
a = 5; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·5·(-10)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{249}}{2*5}=\frac{-7-\sqrt{249}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{249}}{2*5}=\frac{-7+\sqrt{249}}{10} $
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